How would I solve 2i/(1+i) ? I know the answer is 1+i but I don't know how to get there. 2i  1 + i 2i(1  i)  {multiplied top and bottom by conjugate of denominator} (1 + i)(1  i) 2i  2i²  {used distributive property on top and foil method on bottom} 1  i² 2i  2(1)  {in imaginary numbers, i² is 1} 1  (1) 2i + 2  {simplified on top and bottom} 1 + 1 2(i + 1)  {factored 2 out of top} 2 = i + 1 {cancelled the 2's} = 1 + i {flipped around} © Algebra House
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